A 50 g mass is attached to a massless spring and allowed to oscillate around an equilibrium according to: y(t) = 1.2*sin( 3.1415*t ) where y is measured in meters and t in seconds 1) What is the amplitude of this motion? ____ m 2) What is the frequency of this motion? ____ Hz 3)What is the period of the motion? ____ s
When of the form, y(t) = A * sin(w*t) A = amplitude w=angular frequency w=2*pi*f in units of rad/s f = w/(2*pi) = frequency in Hz T = 1/f in units of s Identifying the coefficients: A = 1.2 meters w = pi (=3.1415), so f = 2pi/(pi) = 2 Hz T = 1/f = 1/2 s = 0.5 s All other information in the problem is superfluous, e.g. the picture and the mass.