since the final value is 1, obviously this is decay, and formula is 1 = 24(1-b)^x this has two unknowns, so what you can do is to assume different decay rates (b) and find the time period (x) (1-b)^x = (1/24) eg for a decay rate of 10%, ie 0.1 0.9^x = 1/24 x = ln(1/24)/ln .9 = 30.16 (yrs, say) similarly, for a decay rate of 0.15, x = ln(1/24)/ln 0.85 = 19.55 yrs i do hope something like this is expected !