Find the zeros and the multiplicity of it? f(x) = x(x-2)^2 (x+3) What about the end behavior? rise/falls to the left/right
Since (x - 2) is a factor twice, 2 is a zero of multiplicity 2. Since (x + 3) is a single factor, -3 is a zero of multiplicity 1. If x is a big negative, you have neg ? pos ? neg = positive so it starts high and falls If x is a big positive you have pos ? pos ? pos = pos so it ends high, rising